Set Implementation using Array

import java.util.Arrays;
import java.util.HashSet;
import java.util.Set;

public class SetArrayImplementation {

 public static void main(String[] args) {

  String[] array1 = { "A", "B", "C", "D" };
  String[] array2 = { "A", "E", "F", "G" };
  String[] array3 = { "F", "G", "H", "I" };
  /* Union */
  union(array1, array2, array3);
  /* Intersection */
  intersection(array1, array2);
  /* Set Difference */
  setDifference(array1, array2);
 }

 private static void setDifference(String[] array1, String[] array2) {
  Set<String> hashSet = new HashSet<String>();
  hashSet.addAll(Arrays.asList(array1));
  hashSet.retainAll(Arrays.asList(array2));
  System.out.println("Set Difference : " + hashSet);

 }

 private static void intersection(String[] array1, String[] array2) {

  Set<String> hashSet = new HashSet<String>();
  hashSet.addAll(Arrays.asList(array1));
  hashSet.removeAll(Arrays.asList(array2));
  System.out.println("Intersection :" + hashSet);
 }

 private static void union(String[] array1, String[] array2, String[] array3) {

  Set<String> hashSet = new HashSet<String>();
  hashSet.addAll(Arrays.asList(array1));

  hashSet.addAll(Arrays.asList(array2));

  hashSet.addAll(Arrays.asList(array3));
  System.out.println("Union :" + hashSet);
 }
}

Output:
 
 Union :[D, E, F, G, A, B, C, H, I]
 Intersection :[D, B, C]
 Set Difference : [A] 

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